-5x^2+10=-8x

Solution for -5x^2+10=-8x equation:

-5x^2+10=-8x

We move all terms to the left:

-5x^2+10-(-8x)=0

We get rid of parentheses

-5x^2+8x+10=0

a = -5; b = 8; c = +10;
Δ = b2-4ac
Δ = 82-4·(-5)·10
Δ = 264
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{264}=\sqrt{4*66}=\sqrt{4}*\sqrt{66}=2\sqrt{66}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(8)-2\sqrt{66}}{2*-5}=\frac{-8-2\sqrt{66}}{-10}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(8)+2\sqrt{66}}{2*-5}=\frac{-8+2\sqrt{66}}{-10}
$